Calculating and putting all possibilities of 36 ncr 10 in a list in python

Calculating and putting all possibilities of 36 ncr 10 in a list in Python can be achieved in different ways. In this article, we will explore three different approaches to solve this problem.

Approach 1: Using the math module

import math

def calculate_ncr(n, r):
    return math.comb(n, r)

n = 36
r = 10

possibilities = [calculate_ncr(n, i) for i in range(r+1)]
print(possibilities)

In this approach, we utilize the math.comb() function from the math module to calculate the combination. We iterate over the range of values from 0 to r (inclusive) and calculate the combination for each value. The results are stored in the possibilities list.

Approach 2: Using a recursive function

def calculate_ncr(n, r):
    if r == 0 or r == n:
        return 1
    else:
        return calculate_ncr(n-1, r-1) + calculate_ncr(n-1, r)

n = 36
r = 10

possibilities = [calculate_ncr(n, i) for i in range(r+1)]
print(possibilities)

In this approach, we define a recursive function calculate_ncr() that calculates the combination using the formula nCr = (n-1)C(r-1) + (n-1)Cr. We start with the base cases where r is 0 or equal to n, which returns 1. For other values, we recursively call the function with reduced values of n and r. The results are stored in the possibilities list.

Approach 3: Using the itertools module

import itertools

n = 36
r = 10

possibilities = list(itertools.combinations(range(n), r))
print(possibilities)

In this approach, we utilize the combinations() function from the itertools module to generate all possible combinations of length r from the range of values from 0 to n-1. The results are stored in the possibilities list.

After evaluating all three approaches, it can be concluded that Approach 1 using the math module is the most efficient and straightforward solution for calculating and putting all possibilities of 36 ncr 10 in a list in Python. It provides a built-in function specifically designed for calculating combinations, resulting in cleaner and more readable code.

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11 Responses

    1. I personally believe that Approach 2 is the way to go. It adds an element of excitement and creativity to the challenge. Who needs efficiency when you can have fun? But hey, thats just my opinion. Lets hear what others have to say! 😄

    1. Ive tried approach 2 and found it to be incredibly efficient. It streamlined my workflow like nothing else. Give it a shot and see for yourself!

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