# Add n business days to a given date ignoring holidays and weekends in python

When working with dates in Python, it is often necessary to add a certain number of business days to a given date. However, it is important to exclude weekends and holidays from the calculation. In this article, we will explore three different ways to solve this problem using Python.

## Solution 1: Using the datetime and timedelta modules

``````from datetime import datetime, timedelta

current_date = start_date
while num_days > 0:
current_date += timedelta(days=1)
if current_date.weekday() < 5:  # Exclude weekends
num_days -= 1
return current_date

start_date = datetime(2022, 1, 1)
num_days = 5
print(result)``````

In this solution, we use the datetime module to represent dates and the timedelta module to perform date arithmetic. We start by defining a function called add_business_days that takes a start_date and the number of days to add. We initialize a current_date variable with the start_date and iterate until we have added the desired number of business days. Inside the loop, we increment the current_date by one day and check if it is a weekday (Monday to Friday). If it is, we decrement the num_days counter. Finally, we return the resulting date.

## Solution 2: Using the pandas library

``````import pandas as pd

current_date = pd.to_datetime(start_date)
while num_days > 0:
current_date += pd.DateOffset(days=1)
if current_date.weekday() < 5:  # Exclude weekends
num_days -= 1
return current_date

start_date = '2022-01-01'
num_days = 5
print(result)``````

In this solution, we leverage the power of the pandas library, which provides extensive functionality for working with dates and times. We define a function called add_business_days that takes a start_date and the number of days to add. We convert the start_date to a pandas datetime object using the pd.to_datetime function. Then, we iterate until we have added the desired number of business days, incrementing the current_date by one day at each iteration. We also exclude weekends by checking the weekday attribute of the current_date. Finally, we return the resulting date.

## Solution 3: Using the dateutil library

``````from datetime import datetime
from dateutil.relativedelta import relativedelta
from dateutil.rrule import rrule, DAILY

current_date = datetime.strptime(start_date, '%Y-%m-%d')
business_days = list(rrule(DAILY, dtstart=current_date, byweekday=(0, 1, 2, 3, 4)))
return result_date.strftime('%Y-%m-%d')

start_date = '2022-01-01'
num_days = 5
print(result)``````

In this solution, we utilize the dateutil library, which provides powerful date and time manipulation capabilities. We define a function called add_business_days that takes a start_date and the number of days to add. We convert the start_date to a datetime object using the datetime.strptime function. Then, we generate a list of business days using the rrule function from the dateutil.rrule module, specifying the start_date and the byweekday parameter to exclude weekends. Finally, we return the desired business day by indexing the business_days list and converting it back to a string format.

After exploring these three solutions, it is clear that Solution 2, which utilizes the pandas library, is the most concise and efficient option. Pandas provides a high-level interface for working with dates and times, making it easier to handle business day calculations. Additionally, pandas offers various advanced features and optimizations, making it a powerful tool for date manipulation tasks.

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### 6 Responses

1. Braylon says:

Solution 2 with pandas seems cool, but Id rather stick with Solution 1. Whats your take, peeps?

2. Dax says:

Solution 3 with the dateutil library seems like a smart choice. Who needs weekends and holidays anyway? 🤷‍♀️

3. Ensley Douglas says:

Solution 2 using pandas is a game-changer! So much simpler and efficient. Love it!

4. Moises says:

Solution 2 using pandas sounds cool, but can we use numpy instead? #codingconfusion

Solution 2 with pandas seems like a fun and quirky way to add business days! 🐼🎉

6. Alondra says:

I prefer Solution 1 because datetime and timedelta are the OGs. 💪🏻📅