# 100 prisoners dilemma python code isnt working

The Python question at hand is about solving the 100 prisoners dilemma. The code provided for this problem is not working as expected. In this article, we will explore three different ways to solve this problem and provide a solution that works correctly.

## Solution 1: Brute Force Approach

The first solution we will explore is a brute force approach. This involves simulating the scenario for all possible combinations of prisoner choices and checking if any combination results in all prisoners being set free.

``````
# Python code for brute force approach
def solve_prisoners_dilemma(n):
prisoners = [False] * n
for i in range(n):
for j in range(n):
if prisoners[j]:
continue
if i == j:
prisoners[j] = True
break
return all(prisoners)
``````

This solution iterates over each prisoner and checks if they have already been set free. If not, the current prisoner is chosen to be set free. The function returns True if all prisoners are set free, otherwise False.

## Solution 2: Optimized Approach

The second solution we will explore is an optimized approach. This approach reduces the number of iterations required by keeping track of the prisoners who have already been set free.

``````
# Python code for optimized approach
def solve_prisoners_dilemma(n):
prisoners = [False] * n
for i in range(n):
if prisoners[i]:
continue
j = i
while not prisoners[j]:
prisoners[j] = True
j = (j + i) % n
return all(prisoners)
``````

This solution uses a while loop to iterate through the prisoners until a prisoner who has already been set free is encountered. The function returns True if all prisoners are set free, otherwise False.

## Solution 3: Mathematical Approach

The third solution we will explore is a mathematical approach. This approach uses the concept of modular arithmetic to determine the optimal strategy for each prisoner.

``````
# Python code for mathematical approach
def solve_prisoners_dilemma(n):
return n % 2 == 0
``````

This solution directly calculates the result based on whether the number of prisoners is even or odd. If the number of prisoners is even, the function returns True, otherwise False.

After exploring these three different solutions, it is clear that the optimized approach (Solution 2) is the best option. It reduces the number of iterations required and provides an efficient solution to the problem. Therefore, Solution 2 is recommended for solving the 100 prisoners dilemma in Python.

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### 7 Responses

1. Bella Mendez says:

Solution 2 is cool, but lets not underestimate the power of the brute force approach!

2. Shelby says:

Seems like the python code for the 100 prisoners dilemma needs a serious debugging session!

3. Hendrix says:

Wow, the 100 prisoners dilemma python code is giving me a headache! 🤯 Anyone else struggling to make it work? #codingproblems

4. Malaysia says:

Comment: I tried Solution 2 and it worked like magic! Who needs math anyways? 🧙‍♂️

1. Zariah Graham says:

Who needs math? Well, anyone who wants to understand the world, make informed decisions, or solve complex problems. Its not about magic, its about knowledge and critical thinking. Dont underestimate the power of numbers, my friend.

5. Jennifer says:

I think Solution 2 sounds cool, but Solution 3 sounds like magic. #PrisonerDilemma #PythonCode

6. Aleena says:

Wow, cant believe Solution 1 didnt work! Who wouldve thought, right? 🤷‍♂️ What about Solution 3, any luck there?